x^2-7x+27=5

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Solution for x^2-7x+27=5 equation:


Simplifying
x2 + -7x + 27 = 5

Reorder the terms:
27 + -7x + x2 = 5

Solving
27 + -7x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
27 + -5 + -7x + x2 = 5 + -5

Combine like terms: 27 + -5 = 22
22 + -7x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
22 + -7x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-22' to each side of the equation.
22 + -7x + -22 + x2 = 0 + -22

Reorder the terms:
22 + -22 + -7x + x2 = 0 + -22

Combine like terms: 22 + -22 = 0
0 + -7x + x2 = 0 + -22
-7x + x2 = 0 + -22

Combine like terms: 0 + -22 = -22
-7x + x2 = -22

The x term is -7x.  Take half its coefficient (-3.5).
Square it (12.25) and add it to both sides.

Add '12.25' to each side of the equation.
-7x + 12.25 + x2 = -22 + 12.25

Reorder the terms:
12.25 + -7x + x2 = -22 + 12.25

Combine like terms: -22 + 12.25 = -9.75
12.25 + -7x + x2 = -9.75

Factor a perfect square on the left side:
(x + -3.5)(x + -3.5) = -9.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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